Question

The ages of three siblings combined is 27. The oldest is twice the age of the youngest. The middle child is 3 years older than the youngest. Write and solve an equation to find the ages of each sibling.

Please help!

Answer 1

x+y+z=27
lets say
x<y<z

z=2x
y=3+x

sub

x+y+z=27
x+3+x+2x=27
4x+3=27
minus 3
4x=24
divide by 4
x=6

y=3+x
y=3+6
y=9

z=2x
y=2(6)
y=12


ages are

6,9,12