Question

Consider the quadratic function f(x) = x2 – 8x – 4. What is the value of the leading coefficient

Answer 1

easey
f(x)=ax^2+bx+c
leading coefient is a
f(x)=1x^2-8x-4
leading coefient is 1

Answer 2

The answer is

the value of the leading coefficient is equal to
`1`

Explanation:

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`f(x)=x^(2) -8x-4`

equate the function to zero

`x^(2) -8x-4=0`

so

`a=1\\b=-8\\c=-4`

the value of the leading coefficient is equal to a

`a=1`