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Consider the following equilibrium: 2SO3(g) 2SO2(g) + O2(g) Which statement correctly describes the rate of decomposition of SO3 at equilibrium? A.It equals the rate of formation of O2. B.It equals the rate of formation of SO3. C.It is less than the rate of formation of O2. D.It is less than the rate of formation of SO3.

2 Answers

4 votes
B. It equals the rate of the formation of SO3
answered
User Zari
by
7.3k points
4 votes

The correct answer is option B. It equals the rate of formation of SO₃.

At equilibrium the rate of the forward reaction is always equal to the rate of the backward reaction. The concentration of the reactants and products do not change with time at equilibrium.

The rate of decomposition of SO₃ at equilibrium is equal to the rate of formation of SO₃. At equilibrium the concentration of SO₃ will remain constant.

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User Qqwy
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8.2k points
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