What is the ph of 2.34 * 10^-5 naoh solution?

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asked May 6, 2017 61.6k views

1 Answer

Nhydock · Answer 1 · 2017-05-12T17:01:35+0000

NaOH = Na⁺ + OH⁻

pOH = - log [ OH⁻ ]

pOH = - log [ 2.34x10⁻⁵ ]

pOH = 4.63

Therefore:

pH + pOH = 14

pH + 4.63 = 14

pH = 14 - 4.63

pH = 9.37

What is the ph of 2.34 * 10^-5 naoh solution?

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