Question

A basketball star exerts a force of 3225 n (average value) upon the gym floor in order to accelerate his 76.5-kg body upward. determine the acceleration of the player and speed if force continues for 0.150

Answer 1

F = m . g = 76.5 x 9..8 = 749.7
Net Force = 3225 - 749.7 = 2475.3

F = m.a
2475.3 = 76.5 a

a = 32.35



V = at + v1
V = at + 0
V = 32.35 x 0.15
V = 4.8525

Hope this helps