Determine how many moles of ba(oh)2 are required to completely neutralize 0.445 mol of ch3cooh.

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asked Jan 1, 2017 142k views

1 Answer

Tim Kamm · Answer 1 · 2017-01-06T00:45:53+0000

mole ratio:

2 CH3COOH + Ba(OH)2 = Ba(CH3COO)2 + 2 H2O

2 moles CH3COOH -------------- 1 mole Ba(OH)2
0.445 moles CH3COOH --------- ??

0.445 x 1 / 2

=> 0.2225 moles of Ba(OH)2

Determine how many moles of ba(oh)2 are required to completely neutralize 0.445 mol of ch3cooh.

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