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4 votes
Find the square of the leg b of this right triangle a=2b, c=10

1 Answer

4 votes
a^2+b^2=c^2
where c=25 m. and a=2b-10 m.
substitute
(2b-10)^2+b^2=25^2
4b^2-40b+100+b^2=625
5b^2-40b+100=625
divide both sides by 5
b^2-8b+20=125
subtract 20 from both sides
b^2-8b=105
complete the square
take half of 8 and square it=16
i hope this helps =3

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