For this case we have the following system of equations: 
 

 We can write a system of equivalent equations. 
 For this, it is enough to multiply one of the two equations by a scalar. 
 Multiplying the equation 1 by 2, we have:
 

 Therefore, the new system of equations is: 
 

 Answer: 
 A system that is equivalent is: 
 D) 
