Question

An architect is determining the rectangular dimensions of a room. The length measures 6 more than the width. The height is 8 feet less than the length. The sum of all three measures is 46. What are the measurements of the room?

Answer 1

To determine the dimensions of the room, assign variables to the width, length, and height. Set up an equation using the information given and solve for the variables.

Step-by-step explanation:

To determine the dimensions of the room, let's assign variables to the width, length, and height. Let's say the width is 'w' feet, the length is 'w + 6' feet, and the height is 'w + 6 - 8' feet. We know that the sum of all three measures is 46, so we can set up the equation:

w + (w + 6) + (w + 6 - 8) = 46

Simplifying the equation, we get:

3w + 4 = 46

3w = 42

w = 14

Therefore, the width of the room is 14 feet, the length is 20 feet, and the height is 14 - 8 = 6 feet.

Answer 2

first you multiply 6*8 which is the length and the height and you 48. Then you divide by 2 and you get 24 as the width.