Question

A 30 nc charge experiences a 0.047 n electric force. what is the magnitude of electric field at the position of this charge?

Answer 1

Electric force = electric field * charge

F = E*C => E = F / C = 0.047 N / 30 nC = 0.00157 N/nC = 0.00157 * 10^9 N/C = 1.57 * 10^6 N/C