asked 151k views
1 vote
The difference of three times Faye's age and four times Joshua's age is 31. If Faye's age is five more than twice Joshua's age, how old is Faye?

asked
User Polar
by
8.5k points

1 Answer

6 votes
She is 31

F-Faye
J-Joshua

F3-J4=31
F=J2+5
(J2+5)(3)-J4=31
J2+5=31
J2+5-5=31-5
J2=26
J2/2=26/2
J=13

F=13(2)+5
F=26+5
F=31
answered
User Gingemonster
by
8.2k points
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