Question

Find four consecutive integers such that the sum of the second and the fourth is 132

Answer 1

Set this up as a system of equations;
x+2=y
x+y=132

where x is the second number of the sequence, and y is the fourth.

solve for x first;

x + x + 2 = 132 , 2x = 130 , x = 65

Then input x back in to get 65 + 2 = y , or y = 67

So the sequence would be 64, 65, 66, 67 :)