asked 43.6k views
3 votes
The federal limit for cadmium in drinking water is 0.010 mg per liter of solution. What is the molar concentration of a Cd solution that has reached the limit?

2 Answers

7 votes

Answer:


M=8.9x10^(-8)M

Step-by-step explanation:

Hello,

In this case, one can assume 1L as the volume of the solution, so we've got 0.010mg of cadmium. Now, as we're asked to know its molarity, one computes the moles of cadmium as follows:


n_(Cd)=0.010mg*(1x10^(-3)gCd)/(1mgCd)*(1molCd)/(112.4gCd)=8.9x10^(-8)molCd

Now, one obtains the molar concentration (molarity) as shown below:
M=(8.9x10^(-8)molCd)/(1L)\\ M=8.9x10^(-8)M

Best regards.

answered
User Allolex
by
8.8k points
3 votes
Thank you for posting your question here. The molar concentration of a Cd solution that has reached the limit is 8.89x10^-8 mols/L. The equation to be used M=n/L to solve the above problem. Below is the solution:

.010mg/L = .00001g/L
.00001g / 112.41g/mol = 8.89x10^-8 mols/L
answered
User Seho Lee
by
8.2k points
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