Question

Use the dot product to find the magnitude of u if u = 6i - 3j

Answer 1

Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | =
`\sqrt{6 ^(2)+(-3) ^(2) } = √(36+9)= \\ √(45)= √(9*5)=3 √(5)`
Answer:
The magnitude of vector u is 3√5.