Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance BB'

Answer 1

The transformation is:
T : ( x , y ) → ( x + 2, y + 1 )
B ( 1, 3 ) → B` ( 1 + 2, 3 + 1 )
B ` ( 3, 4 )
d ( B B`) = √(( 3 - 1 )² + ( 4 - 3 )² )=
= √ (2² + 1²) = √ 5

Answer 2

`√(5)\ units`

Explanation:

we know that

The rule of the translation is equal to

`(x,y)-----> (x+2,y+1)`

That means

The translations is
`2` units to the right and
`1` unit up

Let

`(x,y)`-------> the coordinates of point B

`(x+2,y+1)`------> the coordinates of point B'

Find the distance

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

substitute

`d=\sqrt{((y+1)-y)^(2)+((x+2)-x)^(2)}`

`d=\sqrt{(1)^(2)+(2)^(2)}`

`d=√(5)\ units`