Question

X (dy/dx) = (y-1/y+1)-y

Answer 1

f'
`( (y-1)/(y+1))-y`=
f'
`( (y-1)/(y+1))`-f'(y) [/tex]=

`(f'(y-1)(y+1)-f'(y+1)(y-1))/((y+1)^2) -1`=

`((f'(y)-f'(1))(y+1)-(f'(y)+f'(1))(y-1))/((y+1)^2) -1`=

`((1-0)(y+1)-(1-0)(y-1))/((y+1)^2) -1`=

`((1)(y+1)-(1)(y-1))/((y+1)^2) -1`=

`((y+1)-(y-1))/((y+1)^2) -1`=

`(y+1-y+1)/((y+1)^2) -1`=

`(2)/((y+1)^2) -1`