Question

A container of water is knocked off a 10.0–meter–high ledge with a horizontal velocity of 1.00 meters/second. Calculate the time it takes for the container to reach the ground.

Answer 1

1.42 hope it helps i would put the steps but that will take way too long

Answer 2

The container to reach the ground at 1.42 sec.

Step-by-step explanation:

Given that,

Height h = 10 m

Velocity = 1 m/s

Using equation of motion for vertical height

`s_(y)=ut-(1)/(2)gt^2+h_(0)`

Where,
`h_(0)` =initial height

u = initial velocity

g = acceleration due to gravity

`s_(y)` = vertical height

Here,
`s_(y)` is zero at ground.

Put the value into the equation

`0=0-(1)/(2)*9.8t^2+10`

`4.9t^2=10`

`t=\sqrt{(10)/(4.9)}`

`t = 1.42\ sec`

Hence, The container to reach the ground at 1.42 sec.