Question

Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?

f(x) = (x + 3)2 + 3
f(x) = (x + 3)2 − 6
f(x) = (x + 6)2 + 3
f(x) = (x + 6)2 − 6

Answer 1

the correct answer is the second one on ed

B)f(x) = (x + 3)2 − 6

just took the test

Answer 2

f(x)=x^2+6x+3
seperate x terms
f(x)=(x^2+6x)+3
take 1/2 of 6 and square it
6/2=3
3^2=9
add negative and positive inside parenthasees
f(x)=(x^2+6x+9-9)+3
factor perfect square
f(x)=((x+3)^2-9)+3
get rid of parenthasees
f(x)=(x+3)^2-9+3
f(x)=(x+3)^2-6

last one is answer