asked 116k views
1 vote
What is the mass in grams of manganese in 0.412 g of Mn3O4

asked
User Orfdorf
by
7.5k points

1 Answer

2 votes
.412 g Mn304/ 1mol * 1 mol Mn304/228.82(MM of Mn3O4 molecule)* 3 mol Mn/1 mol Mn3O4 = .00540 mol Mn *54.94 g/mol = .296 g Mn
answered
User Anton Tananaev
by
7.8k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.