Question

Solve the literal equation for y; cy+3=6d-2y

Answer 1

cy+3=6d-2y
cy + 2y = 6d - 3
(c + 2)y = 6d - 3
y = (6d - 3)/(c + 2)

Answer 2

I will do my best to explain what is done, but feel free to ask if you have questions on what I did:

`cy+3=6d-2y`
bring all the "y"s to one side

`cy+3-3=6d-2y-3`

`cy+2y=6d-3-2y+2y`
this should be your result...

`cy+2y=6d-3`
now divide y out to isolate it:

`y(c+2)=6d-3`
then divide our c+2 so your y is alone

`(y(c+2))/(c+2)= (6d-3)/(c+2)`
you should get this as your answer:

`y= (6d-3)/(c+2)`