Question

What is the value of h(−2) when h(x)=3x+1 ?

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Answer 1

we have

`h(x)=3x+1` --------> equation
`1`

we know that

To find the value of
`h(-2)` substitute the value of
`x=-2` in the equation
`1`

so

For
`x=-2`

`h(-2)=3*(-2)+1`

`h(-2)=-6+1`

`h(-2)=-5`

therefore

the answer is

`h(-2)=-5`

Answer 2

sub -2 for x
h(-2)=3(-2)+1
h(-2)=-6+1
h(-2)=-5