Question

What's 3x-5y=9;x=-1,0,1?

Answer 1

one easy way is first solve for y
3x-5y=9
minus 3x both sides
-5y=-3x+9
divide both sides by -5
y=
`(3x-9)/(5)`

so

if x=-1
y=
`(3(-1)-9)/(5)`
y=
`(-3-9)/(5)`
y=
`(-12)/(5)`

if x=0
y=
`(3(0)-9)/(5)`
y=
`(0-9)/(5)`
y=
`(-9)/(5)`

if x=1
y=
`(3(1)-9)/(5)`
y=
`(3-9)/(5)`
y=
`(-6)/(5)`