Question

The six is in the dent in the square root sign and 128 is under it

Answer 1

remember

`\sqrt[n]{x^m} =x^ (m)/(n)`

so
128=2^7

`\sqrt[6]{2^7} =2^ (7)/(6)`=
`(2^ (6)/(6))(2^ (1)/(6))=2 \sqrt[6]{2}`