Question

Help me, please!! Estoy desesperada y no hablo inglês!! Help

Answer 1

`D:x>0\\ \log x+\log x^2+\log x^3=-6\\ \log (x\cdot x^2\cdot x^3)=\log 10^(-6)\\ x^6=10^(-6)\\ x^6=\left((1)/(10)\right)^6\\ \boxed{x=(1)/(10)}`

Answer 2

Log x^n = nLog x
log x + log x^2 + log x^3
Log x + 2 log x +3 log x = -6
6 log x = -6
Log x = -1
X=10^-1 = 1/10
Respuesta final
X=1/10