Question

The specific heat capacity of iron is 450.5. A 15.5 kg block of iron with

an initial temperature of 20 degrees Celsius is heated with 250 J. What will

the final temperature of the iron be?

Answer 1

`T_f=20.03^(\circ) C`

Step-by-step explanation:

Given that,

The specific heat capacity of iron is 450.5 J/g°C

The mass of block of iron, m = 15.5 kg

Initial temperature,
`T_i=20^(\circ) C`

Heat required, Q = 250 J

We need to find the final temperature of the iron. The formula for heat required is given by :

`Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\(Q)/(mc)=(T_f-T_i)\\\\T_f=(Q)/(mc)+T_i\\\\T_f=(250)/(15.5(450.5))+20\\\\T_f=20.03^(\circ) C`

So, the final temperature of the iron is
`20.03^(\circ) C`.