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1 vote
How many grams of nitrogen must be used to form 106 grams of ammonia

asked
User Boksiora
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1 Answer

4 votes
N₂ + 3H₂ ⇒ 2NH₃
1mol : 2mol
28g : 34g
x : 106g


x=(106g*28g)/(34g)\approx87,29g
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User The Impaler
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