Question

Write the point-slope form of the line passing through (2, -12) and perpendicular to y=3x.

Answer 1

y + 12 = - 1/3 (x - 2)

Explanation:

Answer 2

Given point = (2, -12)

We know, the slope of a line perpendicular to another line is the opposite reciprocal.

So slope of the new line will be
`- (1)/(3)`

We know, point slope form is,


`y-y_1=m(x-x_1)\\\\ y-(-12)= -(1)/(3)(x-2)\\\\ \boxed{y+12= -(1)/(3)(x-2)}\\\\y+12= -(x)/(3) + (2)/(3)\\\\y= -(x)/(3) + (2)/(3)-12\\\\y= -(x)/(3) + (2-36)/(3)\\\\ \boxed{y= -(x)/(3) - (34)/(3)}`

The first box is your answer in point-slope form. The second box is your answer in slope-intercept form.