Question

Cu + H2O --> CuO + H2

This equation shows that Cu is either oxidized or reduced? (Choose one)

This equation shows that H2 is either oxidized or reduced? (Choose one)

Answer 1

Answer: Copper is getting oxidized and hydrogen is getting reduced.

Step-by-step explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of this substance is increased and the substance gets oxidized.

`X\rightarrow X^(n+)+ne^-`

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of this substance gets reduced and the substance gets reduced.

`X^(n+)+ne^-\rightarrow X`

The given chemical reaction is:

`Cu+H_2O\rightarrow CuO+H_2`

The half reactions for the given above chemical reaction is:

Oxidation half reaction:
`Cu\rightarrow Cu^(2+)+2e^-`

Reduction half reaction:
`2H^++2e^-\rightarrow H_2`

As, copper is loosing electrons. so, it is getting oxidized and hydrogen is gaining electrons. So, it is getting reduced.

Answer 2

In the reduction-oxidation reaction given, Cu is reduced because it gained 2 electrons, on the other hand H2 is oxidized because it gained one electron. I hope this helps.