asked 203k views
5 votes
The half life of carbon-14 is 5,730 years, assuming you start with 100% of carbon-14, what is the expression for the percent, p(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 20,000 years old?

hint: the exponential equation for half life s p(t)=ao(0.5)^t/h, where p(t) is the percent of carbon-14 remaining, ao, is the initial amount (100%), t is age of organism in years, and h is the half life.

a. p(t)=100(0.5)^5,730t, 29% remaining
b. p(t)=100(0.5)^5,730/t, 91% remaining
c. p(t)= 5,730(0.5)^100t, 5,710 remaining
d. p(t)=100(0.5)^t/5,730, 9% remaining

asked
User Ayako
by
7.7k points

1 Answer

7 votes
the anwser to this is c i just had it on a test
answered
User Illabout
by
8.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.