Question

an airplane at t(80,20) needs to fly both u(20,60) and v(110,85). what is the shortest possible distance for the trip? explain: what type of info did you need to find it and how can you use a diagram to help you?

Answer 1

We need to find the distances : TU, TV and VU.
TU = √ ( x 2 - x 1)² + ( y 2 - y 1 )²
TU = √ ( 60² + 40² ) = √ (3600 + 1600 ) = √5200 = 72.111
TV = √ ( 30² + 65² ) = √ ( 900 + 4225 ) = √5125 = 71.589
VU = √ ( 90² + 25² ) = √ ( 8100 + 625 ) = √8725 = 93.408
The shortest trip : T → V → U.
The shortest distance:
TV + VU = 71.589 + 93.408 = 164.997