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A submarine went down 800 feet below sea level to Point A, then traveled up to Point B, which was 160 feet below sea level. Write the fraction that relates the distance traveled by the submarine from Point A to Point B to the depth of Point A?

1 Answer

1 vote
The depth of Point A: 800 ft.
The depth of the Point B : 160 ft.
The distance from the point A to point B:
800 - 160 = 640 ft.
The fraction is:
640 / 800 = 4/5
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User Francisco QV
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