How many moles of H3PO4 are in 94.052 grams of H3PO4?

asked Nov 15, 2017 20.7k views

4 votes

by Veno

8.1k points

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2 votes

$m=94,052g\\ M=97,995(g)/(mol)\\\\ n=(m)/(M)=(94,052g)/(97,995(g)/(mol))\approx0,96mol$

Minki answered Nov 20, 2017

by Minki

8.3k points

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asked Oct 6, 2024 198k views

Poiz asked Oct 6, 2024

by Poiz

7.9k points

1 answer

5 votes

198k views

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