How many different batting orders from a starting roster of nine players can a baseball manager make assuming he always lets the pitcher bat last? 362,880 40,320 8

Question

asked Aug 20, 2017 233k views

1 Answer

Paula Hasstenteufel · Answer 1 · 2017-08-25T11:50:39+0000

If the pitcher is always the last to bat, the number of different batting orders is:
8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320
The answer is 40,320