Register

What is the value of ƒ(– 6) when ƒ(x) = x2 + 8x + 10?

What is the value of ƒ(– 6) when ƒ(x) = x2 + 8x + 10?
asked 3.1k views
1 vote
What is the value of ƒ(– 6) when ƒ(x) = x2 + 8x + 10?

asked
User Bgh
by
8.5k points

1 Answer

5 votes

f(x)= x^(2) +8x+10

f(-6) = (-6)^2+8(-6)+10

f(-6)=36-48+10 = -2

f(-6)=-2
answered
User Phil Booth
by
8.6k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!