Question

61.0 mol of P4O10 contains how many moles of P

Answer 1

61mol * 4 = 244moles of P

Answer 2

244 moles of phosphorus are present in 61.0 moles of
`P_4O_(10)`.

Step-by-step explanation:

Moles of
`P_4O_(10)` = 61.0 moles

1 mol of
`P_4O_(10)` contains 4 moles of phosphorus.

Then 61.0 moles of
`P_4O_(10)` will contain:

`61.0 mol* 4=244 mol` of phosphorus

244 moles of phosphorus are present in 61.0 moles of
`P_4O_(10)`.