What is the solution to the linear equation d-10-2d+7=8+d-10-3d

asked May 22, 2017 196k views

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5 votes

d-10-2d+7 = 8 + d- 10 -3d
d-2d-10+7 = 8-10 +d -3d
-d-3=-2-2d
-d+2d=3-2
d=1

Final answer: C. d=1

John Tyner answered May 24, 2017

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4 votes

d-10-2d+7 = 8 + d- 10 -3d

=> d -2d -10+7 = 8 -10 +d - 3d
=>-d - 3 = -2 -2d
=>-d+2d = -2 +3
=> d = 1 ..

Hope it helps !!!

Simon Klee answered May 27, 2017

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