asked 227k views
5 votes
The function f(x) = 582(7)x represents the growth of a mosquito population every year in a remote swamp. Troy wants to manipulate the formula to an equivalent form that calculates every 2 months, not every year. Which function is correct for Troy's purposes?

2 Answers

6 votes

Answer:f(x)=582(7^1/6)^6x

Explanation:

i took the test

answered
User LugiHaue
by
7.5k points
2 votes

Answer: The required function is,


f(x)=582(7^(1)/(6))^(6x)

Explanation:

Since, the population which is increasing with the constant factor is,


P(x)=ab^x

Where, a is the initial population,

b is the growth factor per period,

x is the number of periods.

Here, the given function that represents the mosquito population after x years,


f(x)=582(7)^x

Where, 7 is the growth factor per year,

Since, 12 months = 1 year,

2 month = 1/6 year.

Also, we can write,


582(7)^x=582(7)^{(1)/(6)* 6x}=582(7^(1)/(6))^(6x)


\implies f(x)=582(7^(1)/(6))^(6x)

Which is the required equivalent function that shows the population of mosquito is increasing in every 2 month by the growth factor
7^(1)/(6).

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.