Given the function f(x) = log5(x + 1), find the value of f−1(2).

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George Davis · Answer 1 · 2017-03-26T07:50:15+0000

f ( x ) = log(5) ( x + 1 )
y = log (5) ( x + 1 )
x + 1 = 5^y
x = 5^y - 1
f (-1) ( x ) = 5^x - 1
f ( -1 ) ( 2 ) = 5^2 - 1 = 25 - 1 = 24