Question

1)What are the first five terms of the sequence given by the formula an=4n+1 ?

a. 1,5 ,9,13,17
b. 9,13,17,21,25
c. 5,9,13,17,21
d. 4,8,12,16,20

2)Write a recursive definition for the sequence 8,6,4,2 ...
a. a1=8, an=an-1-2
b. a1=2, an=an-1+6
c. a1=8,an=an-1+2
d. a1=2, an=an-1+8

Answer 1

we are asked to determine the first five terms of the sequence given by the formula an=4n+1, if n is equal to 1 to 5, then an is equal to 5, 9, 13, 17, 21. Answer is A. In 2, given the sequence 8,6,4,2 then the expression is a1=8, an = an-1-2

Answer 2

Answer:1) c. 5,9,13,17,21

2) a. a1=8, an=an-1 -2

Step-by-step explanation: 1) an=4n+1

⇒ a1=4×1+1=5

a2=4×2+1=9

a3=4×3+1=13

a4=4×4+1=17

a5=4×5+1=21

2) clearly a1=8 and then the terms of series are decreasing by 2

so, an=an-1 -2