Question

Iron has a density of 7.86 g/cm^3. Calculate the volume (in dL) of a piece of iron having a mass of 3.56 kg . Note that the density is provided in different units of volume and mass than the desired units of volume (dL) and the given units of mass (kg). You will need to express the density in kg/dL (1 cm3 = 1 mL) before calculating the volume for the piece of iron.

Answer 1

1 g/cm³ --------------- 0.1 kg/dL
7.86 g/cm³ ---------- ?

7.86 x 0.1 / 1 => 0.786 kg/dL

D = m / V

0.786 = 3.56 / V

V = 3.56 / 0.786

V = 4.529 dL

hope this helps!

Answer 2

Volume of the piece of iron = 4.53 dL

Step-by-step explanation:

Density (d) of a given substance is the ration of its mass (m) to the volume (v)

`d = (m)/(v) \\\\v = (m)/(d)`

From the given information:

Density of iron = 7.86 g/cm³

Convert density into units of kg/dL

1 kg = 10³ g

1 dL = 10² cm³

`=(7.86g*1 kg)/(10^(3)g ) *(10^(2)cm^(3))/(1cm^(3)*1dL) =0.786 kg/dL`

Mass of iron = 3.56 kg

Therefore,

`volume = (3.56kg)/(0.786kg/dL) =4.53 dL`