Question

Question 13 please anyone ??

Answer 1

here is how to solve it:
1) isolate x for x+y=2:
x=2-y
2)now plug this value in 3x^2-y^2=1
3(2-y)^2-y^2=1
simplify to get 2y^2-12y+11=0
and you get:
`y_1=3+ \sqrt{ (7)/(2) } ,y_2=3- \sqrt{ (7)/(2) }`

3)plug these(y1,y2) values in x+y=2
and you get:
`x_1=-1- \sqrt{ (7)/(2) } ,x_2=-1+ \sqrt{ (7)/(2) }`
hope that i helped