Question

Chromium-51 is a radioactive isotope used to label red blood cells to identify if they remain intact in the body. It has a half-life of 27.7 days. If 0.25 mg is an approximate dose amount, how much remains after 83.1 days?

Answer 1

`N(t)=N_((0))*((1)/(2))^{\frac{t}{\tau_{(1)/(2)}}}\\\\ N_(0)=0,25mg\\ t=83,1days\\ \tau_{(1)/(2)}=27,7days\\\\\\ N(t)=0,25mg*((1)/(2))^{(83,1)/(27,7)}=0,25mg*((1)/(2))^(3)=0,25mg*(1)/(8)=0,03125mg`