When 6.25 grams of pure iron are allowed to react with oxygen,a black oxide forms.if the product weighs 8.15g,what is the empirical formula of the oxide?

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asked Jan 20, 2017 139k views

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Yaman KATBY · Answer 1 · 2017-01-24T07:36:57+0000

moles Fe = 6.25 g / 55.847 g/mol=0.112

mass O = 8.15 - 6.25 =1.90 g

moles O = 1.90 g/ 15.999 g/mol=0.119

the ratio is 1 : 1 and the compound is FeO ( iron (II) oxide)

When 6.25 grams of pure iron are allowed to react with oxygen,a black oxide forms.if the product weighs 8.15g,what is the empirical formula of the oxide?

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