$\left((1)/(2)\right)^2-6\cdot\left(2-(2)/(3)\right)\\\\=(1)/(4)-6\cdot2+6\cdot(2)/(3)=(1)/(4)-12+2\cdot2\\\\=(1)/(4)-12+4\\\\=(1)/(4)-8=\boxed{-7(3)/(4)}$

Aaron T Harris answered May 29, 2017

by Aaron T Harris

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Simplify. (½) ²− 6(2−2/3)

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