Question

What are the roots of -12x^2 11x − 3 = 0?

Answer 1

`x= (-b\pm√(b^2-4ac))/(2a) \\=(-(-11)\pm√((-11)^2-(4*12*3)))/(2*12)\\=(11\pm√(121-144))/(24)\\=(11\pm√(-23))/(24)\\=(11+i√(23))/(24)\ or \ (11-i√(23))/(24)`12x^2 - 11x + 3 = 0