Question

Cosine is the square root of 3 over 2. How do I find the secant expression without a square root in the denominator by rationalizing the denominator?

Answer 1

than cos = sqrt3 /2 so

sec = 1/(sqrt3 /2)

sec = 2/sqrt3

sec = 2sqrt3 /3

hope helped

Answer 2

Hello,


`cos(x)= ( √(3) )/(2) \\ sec(x)= (1)/(cos(x)) = (1)/(( √(3) )/(2)) =( 2*√(3) )/(√(3)*√(3))=(2*√(3))/(3)`