menu
Qamnty
Login
Register
My account
Edit my Profile
Private messages
My favorites
Solve the following word problem. use x for the unknown value. the average cost of a car in 2013 is said to be 5 less than twice the cost of a car in 2009. if the average cost o…
Ask a Question
Questions
Unanswered
Tags
Ask a Question
Solve the following word problem. use x for the unknown value. the average cost of a car in 2013 is said to be 5 less than twice the cost of a car in 2009. if the average cost o…
asked
Jun 21, 2017
191k
views
4
votes
solve the following word problem. use x for the unknown value. the average cost of a car in 2013 is said to be 5 less than twice the cost of a car in 2009. if the average cost of a car in 2013 is $25,000. how much was the average cost of a car in 2009?
Mathematics
high-school
Anudeep Bulla
asked
by
Anudeep Bulla
8.2k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
4
votes
Let the average cost of car in 2009 be $x, then the average cost of a car in 2013 is 2x - 5
25,000 = 2x - 5
2x = 25,000 + 5 = 25,005
x = 25,005/2 = $12,502.50
Valdarin
answered
Jun 24, 2017
by
Valdarin
7.8k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
No related questions found
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.
Categories
All categories
Mathematics
(3.7m)
History
(955k)
English
(903k)
Biology
(716k)
Chemistry
(440k)
Physics
(405k)
Social Studies
(564k)
Advanced Placement
(27.5k)
SAT
(19.1k)
Geography
(146k)
Health
(283k)
Arts
(107k)
Business
(468k)
Computers & Tech
(195k)
French
(33.9k)
German
(4.9k)
Spanish
(174k)
Medicine
(125k)
Law
(53.4k)
Engineering
(74.2k)
Other Questions
How do you can you solve this problem 37 + y = 87; y =
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search Qamnty