asked 74.8k views
1 vote
24x^3=10x^2+4x I know the roots for this equation but I cannot figure out the check.

1 Answer

4 votes

24x^3=10x^2+4x \\ 24x^3-10x^2-4x=0\\ 2x(12x^2-5x-2)=0\\ 2x(12x^2+3x-8x-2)=0\\ 2x(3x(4x+1)-2(4x+1))=0\\ 2x(3x-2)(4x+1)=0\\ x=0 \vee x=(2)/(3) \vee x=-(1)/(4)
answered
User Hassane
by
7.8k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.