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K(x)=8x+7q, evaluate k(2q^2+3q)

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asked Dec 5, 2017 232k views

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K(x)=8x+7q, evaluate k(2q^2+3q)

Mathematics
high-school

Vpalade asked

by Vpalade

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k(x)= 8x + 7q
⇒ k(2q²+3q) = 8(2q² + 3q) +7q
= 16q² + 24q + 7q
= 16q² + 31q

Valerij answered Dec 10, 2017

by Valerij

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K(x)=8x+7q, evaluate k(2q^2+3q)

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