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Lim as x approaches 5 from the right (x-5)/(x^2-25)

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\lim_(x \to 5^+) (x-5)/(x^2-25) = \lim_(x \to 5^+) (x-5)/((x-5)(x+5)) = \lim_(x \to 5^+) (1)/(x+5) = \infty
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User Zhiyuan Sun
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